In Fig. 15.105, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of ΔEFG.


We know that,

If a triangle and a parallelogram are on the same base and between the same parallel then the angle of triangle is equal to the half of the parallelogram


So, triangle EPG and parallelogram ABCD are on the same base and between same parallels. The


We know that,


Area of parallelogram = Base * Height


Now,


Area ( = * Area of ABCD


= * AB * AD


= * 10 * 5


= 25 cm2


Hence,


Area ( is 25 cm2


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