P is any point on base BC of ΔABC and D is the mid-point of BC. DE is drawn parallel to PA to meet AC at E. If then find area of ΔEPC.
Given that,
Area ( = 12 cm2
D is the mid-point of BC
So,
AD is the median of triangle ABC,
Area ( = Area (
=
* Area (
Area ( = Area (
=
* 12
= 6 cm2 (i)
We know that,
Area of triangle between the same parallel and on the same base
Area ( = Area (
Area ( + Area (
= Area (
+ Area (
Area ( = Area (
(ii)
ME is the median of triangle ADC,
Area ( = Area (
+ Area (
Area ( = Area (
+ Area (
[From (ii)]
Area ( = Area (
6 cm2 = Area ( [From (i)]
Hence,
Area ( is 6 cm2.