Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with base dimensions 4 m × 3 m?


Given,


Height of shelter = 2.5 m


Base dimensions = l×b = 4m×3m


So,


area of tarapaulin needed = lateral surface area of shelter +area of roof


= 2(l+b)h + l×b


= 2(4+3)2.5 +12 = 47 m2


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