Three cubes of metal whose edges are in the ratio 3 : 4 : 5 are melted down into a single cube whose diagonal is 12cm. Find the edges of three cubes.
Given,
Ratio of edge of 3 cubes = 3:4:5
Diagonal of new cube formed = 12√3 cm
Let edges are = 3x ,4x 5x
Comined volume =
= 216 x3
New diagonal = √3a = 12√3 = a = 12 cm
So, a3 = 216 x3
= 12×12×12 = 216 x3
=
=x =
So , edges are = 3x = 3×2 = 6 cm
=4x = 4×2 = 8cm
= 5x = 5×2 = 10 cm