Two steel sheets each of length a1 and breadth a2 are used to prepare the surfaces of two right circular cylinder —one having volume v1 and height a2 and other having volume v2 and height a1. Then,


In case (i)


2πr= a1


= r = a1/2π


= h1 = a2


So, v1 = πr2h = π×(a1/2π)2h = a12a2/4π…………..(1)


In case (ii)


2πr = a2


= r = a2/2π and h = a1


So, v2 = πr2h = π× (a2/4π)2a1 = a22a1/4π……………….(2)


From equations 1 and 2 …


= a2v1 = a1v2


= v1/a1 = v2/a2 ( so both options (B) and (D) are correct.)

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