Prove that the line joining the mid-point of a chord to the centre of the circle passes through the mid-point of the corresponding minor arc.
Given that,
C is the mid-point of chord AB
To prove: D is the mid-point of arc AB
Proof: In
OA = OB (Radius of circle)
AC = OC (Common)
AC = BC (C is the mid-point of AB)
Then,
(By SSS congruence rule)
∠AOC = ∠BOC (By c.p.c.t)
A
B
Here, D is the mid-point of arc AB