AB is a chord of a circle with centre O and radius 4cm. AB is of length 4cm and divides the circle into two segments. Find the area of the minor segment.
Given,
Radius of circle = 4cm
Length of chord = 4cm
(Hence it makes an equilateral triangle at centre, in which all angle must be = 60°)
Area of sector =
Area of ∆OAB =
Area of minor segment = area of sector – area of ∆OAB