Find the area of the shaded region in Fig.15.72, if AC=24cm, BC=10cm and O is the centre of the circle.
Given,
AC = 24 cm
BC = 10 cm
By Pythagoras theorem
AB2 = AC2 + BC2
= 242+102 = 576 + 100 = 676
AB = = 26cm
Radius of semi-circle with diameter AB = = 13cm
Area of semi-circle = = 265.33cm2
Area of triangle ABC = = 120cm2
So,
Area of shaded region = area of semi-circle – area of triangle
= 265.33 – 120 = 145.33 cm2