Find the squares of the following numbers using the identity 
(i) 395 (ii) 995
(iii)495 (iv) 498
(v) 99 (vi) 999
(vii)599
(i) 395
395 = (400 – 5)2
= (400)2 + 52 – 2 (400) (5)
= 160000 + 25 – 4000
= 156025
995 = (1000 – 5)2
= (1000)2 + 52 – 2 (1000) (5)
= 1000000 + 25 – 10000
= 990025
495 = (500 – 5)2
= (500)2 + 52 – 2 (500) (5)
= 250000 + 25 – 5000
= 245025
498 = (500 – 2)2
= (500)2 + 22 – 2 (500) (2)
= 250000 + 4 – 2000
= 248004
99 = (100 – 1)2
= (100)2 + 12 – 2 (100) (1)
= 10000 + 1 – 200
= 9799
999 = (1000 – 1)2
= (1000)2 + 12 – 2 (1000) (1)
= 1000000 + 1 – 2000
= 998001
(600 – 1)2
= (600)2 + 12 – 2 (600) (1)
= 360000 + 1 – 1200
= 358801
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