Two vertices of an isosceles triangle are (2, 0) and (2, 5). Find the third vertex if the length of the equal sides is 3.
Vertices of an isosceles are: A(2, 0) and B(2, 5).
Let the third vertex is P(x, y)
Using distance formula =![]()
Length of side PA =
units
Length of side PB =
units
Since PA = PB
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On squaring both sides, we get
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,
Also, PA = 3
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On squaring both sides, we get
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On substituting
,
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Using quadratic formula:
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Therefore coordinates of third vertex are:
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