If the point P (2, 2) is equidistant from the points A (-2, k) and B (-2k, -3), find k. Also, find the length of AP.

Coordinates of points are P(2, 2) A(-2, k) and B(-2k, -3)

Using distance formula =

⇒ PA = PB

On squaring both sides, we get

=

=

0

0

0

0

-1, -3

AP = = = 5 units