A (3, 2) and B (-2, 1) are two vertices of a triangle ABC whose centroid G has the coordinates (5/3, - 1/3). Find the coordinates of the third vertex C of the triangle.
Let the vertex of the triangle be A(3, 2), B(-2, 1) and C(x, y)
Let the centroid be G(,
), as it is given that centroid is given at origin.
We know that centroid of a triangle for (x1 , y1), (x2 , y2) and (x3 , y3) is
G(x, y) = ( ,
)
For given coordinates A(3, 2), B(-2, 1) and C(x, y)
(,
) =
,
)
Solving for x and y,
-3 + 2 +x =5 and 2 + = -1
∴ x = 4 and y = -4
Hence, the coordinate of third vertex is C(4, -4).