Given 15 cot A = 8, find sin A and sec A


Consider a right-angled triangle, right-angled at B


Cot A =


It is given that,


Cot A =



Let AB be 8k. Therefore, BC will be 15k, where k is a positive integer.


Applying Pythagoras theorem in ΔABC, we obtain


AC2 = AB2 + BC2


= (8k)2 + (15k)2


= 64k2 + 225k2


= 289k2


AC = 17k


Sin A =


=


Sec A =


=


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