Find the area of an isosceles triangle each of whose equal sides measures 13cm and whose base measures 20cm.
Let,
a = 13 cm
b = 13 cm
And,
C = 20 cm
Now,
s = ![]()
= ![]()
=
= 23 cm
We know that,
Area of triangle = ![]()
= ![]()
= ![]()
= 10![]()
= 10 × 8.306
= 83.06 cm2
Therefore,
Area of isosceles triangle = 83.06 cm2