Find the area of a trapezium whose parallel sides are 9 cm and 6 cm respectively and the distance between these sides is 8 cm.
Given
AB = a = 9 cm
DC = b = 6 cm
Height (h) = 8 cm
We know that area of trapezium is 
x (sum of parallel sides) x height
Therefore, Area of trapezium ABCD = 
x (AB + DC) x h = 
x (9 + 6) x 8 = 60 cm2
Area of Trapezium ABCD = 60cm2
4