In the given figure, the diameter of a circle with center is perpendicular to chord If and calculate the radius of the circle.
Let radius OA = OC = OD = r
Chord AB = 12 cm
OE = OC – CE
⇒ OE = r – 3
AE = (1/2) AB
⇒ AE = (1/2) 12 = 6 cm
In triangle AOE,
OA2 = AE2 + OE2
⇒ r2 = 62 + (r - 3)2
⇒ r2 = 36 + r2 + 9 - 6r
⇒ 6r = 45
⇒ r = 7.5 cm
Hence, radius of circle = 7.5 cm.