In the given figure, is a chord of a circle with center
and
is produced to
such that
Also, is joined and produced to meet the circle in
If
and
prove that
Given, OB = OC
Then, ∠BOC = ∠BCO = y°
External ∠OBA = ∠BOC + ∠BCO = (2y)°
Now,
OA = OB
Then, ∠OAB = ∠OBA = (2y)°
External ∠AOD = ∠OAC + ∠ACO
= ∠OAB + ∠BCO = (3y)°
∴ x° = (3y)°[Given ]