In the given figure, is the center of the circle. If and find the value of

∠BPC + ∠APB = 180°[Because APC is a straight line]

⇒ ∠BPC + 110° = 180°

⇒ ∠BPC = 70°

In triangle BPC,

∠BPC + ∠PBC + ∠PCB = 180°[Sum of angles of triangle]

⇒ 70°+ 25° + ∠PCB = 180°

⇒ ∠PCB = 85°

∴ ∠ADB = ∠PCB = 85°[Angles in the same segment of a circle]