In the adjoining figure, is a chord parallel to diameter
of the circle with center
If
calculate
∠CAD and ∠CBD are in the segment BD.
∴ ∠CAD = ∠CBD [Angles in the same segment of a circle]
∠CAD = 60°
In triangle ACD,
∠CAD + ∠ADC + ∠ACD = 180°[Sum of angles of triangle]
⇒ 60° + 90° + ∠ACD = 180°
⇒ 150° + ∠ACD = 180°
⇒ ∠ACD = 30°
∴ ∠CDE = ∠ACD = 30°[Alternate angles]