Two chords and
of a circle intersect each other at
outside the circle. If
and
find
Two chords AB and CD of a circle intersect each other at P outside the circle.
∴ AP × BP = CP × PD
⇒ (AB + BP) × BP = (CD + PD) × PD
⇒ (6 + 2) × 2 = (CD + 2.5) × 2.5
⇒ 16 = 2.5 CD + 6.25
⇒ 2.5 CD = 9.75
⇒ CD = 3.9 cm