If 
find
(i) f (0)
(ii) f (4)
(iii) f (-5)
(i) We have,
Now,
Put t = 0
f(0) = 4(0)2 - 3(0) + 6
= 4(0) - 3(0) + 6
= 0 – 0 + 6
= 6
Hence,
f(0) = 6
(ii) We have,
Now,
Put t = 4
f(4) = 4(4)2 -3(4) + 6
= 4(16) - 3(4) + 6
= 64 – 12 + 6
= 58
Hence,
f(4) = 58
(iii) We have,
Now,
Put t = -5
f(-5)=4(-5)2 - 3(-5) + 6
= 4(25) - 3(-5) + 6
= 100 + 15 + 6
= 121
Hence,
f(0) = 6
3