Find the zero of the polynomial:

(i) P(x)=x-5

(ii) q(x)=x+4

(iii) p(t)=2t-3

(iv) f(x)=3x+1

(v) g(x)=5-4x

(vi) h(x)=6x-1

(vii) p(x)=ax + b,a≠0

(viii) q(x) = 4x

(ix) p(x)=ax,a≠0

(i) At first,

In order to find the zero of the polynomial we will,

Put p(x) = 0

Now,

We have,

P(x)=x-5

0 = x – 5

x = 5

Hence, 5 is the zero of the given polynomial.

(ii) At first,

In order to find the zero of the polynomial we will,

Put q(x) = 0

Now,

We have,

q(x)=x+4

0 = x + 4

x = - 4

Hence, -4 is the zero of the given polynomial.

(iii) At first,

In order to find the zero of the polynomial we will,

Put p(t) = 0

Now,

We have,

P(t)= 2t - 3

0 = 2t – 3

2t = 3

t = 3/2

Hence, 3/2 is the zero of the given polynomial.

(iv) At first,

In order to find the zero of the polynomial we will,

Put f(x) = 0

Now,

We have,

f(x)= 3x + 1

0 = 3x + 1

3x = -1

x =

Hence, -1/3 is the zero of the given polynomial.

(v) At first,

In order to find the zero of the polynomial we will,

Put g(x) = 0

Now,

We have,

g(x)= 5 – 4x

0 = 5 – 4x

4x = 5

x = 5/4

Hence, 5/4 is the zero of the given polynomial.

(vi) At first,

In order to find the zero of the polynomial we will,

Put h(x) = 6x - 1

Now,

We have,

h(x)= 6x- 1

0 = 6x – 1

6x = 1

x = 1/6

Hence, 1/6 is the zero of the given polynomial.

(vii) At first,

In order to find the zero of the polynomial we will,

Put p(x) = 0

Now,

We have,

p(x)= ax + b

0 = ax + b

ax = -b

x = (-b)/a

Hence, (-b)/a is the zero of the given polynomial.

(viii) At first,

In order to find the zero of the polynomial we will,

Put q(x) = 0

Now,

We have,

q(x)= 4x

0 = 4x

x = 0

Hence, 0 is the zero of the given polynomial.

(ix) At first,

In order to find the zero of the polynomial we will,

Put p(x) = 0

Now,

We have,

p(x)= ax

0 = ax

x = 0

Hence, 0 is the zero of the given polynomial.