is divided by (x-3)

Let, f(x) = 2x³ – 5x² + 9x - 8

Now,

As per the question,

x – 3 = 0

x = 3

Using Remainder theorem,

We know that when f(x)is divided by (x – 3), the remainder so obtained will be f(3).

Hence,

f(3) = 2(3)³ – 5(3)² + 9(3) - 8

= 2(27) – 5(9) + 27 - 8

= 54 – 45 + 19

= 28

Therefore,

The required remainder is 28