Find the value of k for which (x-1) is a factor of
Let, f(x) = 2x3 + 9x2 + x + k
Now, we have
x – 1 = 0
x = 1
Hence,
f(1) = 2 × 13 + 9 × 12 + 1 + k
= 2 + 9 + 1 + k
= 12 + k
As per the question,
(x – 1) is the factor of f(x)
Now, by using factor theorem we get
(x – a) will be a factor of f(x) only if f(a) = 0 and hence f(1) = 0
So,
f(1) = 0
0 = 12 + k
k = -12