Find the value of a for which (x-4) is a factor of
Let, f(x) = 2x3 – 3x2 – 18x + a
Now, we have
x - 4 = 0
x = 4
Hence,
f(4) = 2(4)3 – 3(4)2 – 18 × 4 + a
= 128 – 48 – 72 + a
= 128 – 120 + 8
= 8 + a
As per question,
(x - 4) is the factor of f(x)
Now, by using factor theorem we get
(x – a) will be the factor of f(x) if f(a) = 0 and hence f(4) = 0
So,
f(4) = 8 + a = 0
a = -8