Find the value of a for which (x-4) is a factor of


Let, f(x) = 2x3 – 3x2 – 18x + a


Now, we have


x - 4 = 0


x = 4


Hence,


f(4) = 2(4)3 – 3(4)2 – 18 × 4 + a


= 128 – 48 – 72 + a


= 128 – 120 + 8


= 8 + a


As per question,


(x - 4) is the factor of f(x)


Now, by using factor theorem we get


(x – a) will be the factor of f(x) if f(a) = 0 and hence f(4) = 0


So,


f(4) = 8 + a = 0


a = -8


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