Factorize:

x(x + y)3 – 3x2y (x + y)


We have,



At first we’ll take common from the expression


= x (x + y) [(x + y)2 – 3xy]


= x (x + y) (x2 + y2 + 2xy – 3xy)


= x (x + y) (x2 + y2 – xy)


Hence,


The given expression can be factorized as:



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