Factorize:
(3a - 1)2 – 6a + 2
We have,
At first we’ll take common from the expression
= (3a – 1)2 – 2 (3a – 1)
= (3a – 1) [(3a – 1) – 2]
= (3a – 1) (3a – 3)
= 3(3a – 1) (a – 1)
Hence,
The given expression can be factorized as:
17
Factorize:
(3a - 1)2 – 6a + 2
We have,
At first we’ll take common from the expression
= (3a – 1)2 – 2 (3a – 1)
= (3a – 1) [(3a – 1) – 2]
= (3a – 1) (3a – 3)
= 3(3a – 1) (a – 1)
Hence,
The given expression can be factorized as: