Factorize:
ab(x2 + y2) – xy(a2 + b2)
We have,
At first we’ll take common from the expression
= abx2 + aby2 – a2xy – b2xy
= abx2 – a2xy + aby2 – b2xy
= ax (bx – ay) + by (ay – bx)
= (bx – ay) (ax – by)
Hence,
The given expression can be factorized as:
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