Factorize:
8a3 – b3 – 4ax + 2bx
We know that,
a3 - b3 = (a - b) (a2 + a × b + b2)
Using this formula, we get
= 8a3 – b3 – 2x (2a – b)
= (2a)3 – (b)3 – 2x (2a – b)
= (2a – b) [(2a)2 + 2a (b) + (b)2] – 2x (2a – b)
= (2a – b) (4a2 + 2ab + b2) – 2x (2a – b)
= (2a – b) (4a2 + 2ab + b2 – 2x)