Factorize:
8a3 + 125b3 – 64c3 + 120abc
We know that,
a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]
Using this formula, we get
= (2a)3 + (5b)3 + (-4c)3 – 3 (2a) (5b) (-4c)
= (2a + 5b - 4c) [(2a)2 + (5b)2 + (-4c)2 – (2a) (5b) – (5b) (-4c) – (-4c) (2a)]
= (2a + 5b - 4c) (4a2 + 25b2 + 16c2 – 10ab + 20bc + 8ca)