Factorize:
8 – 27b3 – 343c3 – 126bc
We know that,
a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]
Using this formula, we get
= (2)3 + (-3b)3 + (-7c)3 – 3 (2) (-3b) (-7c)
= (2 - 3b - 7c) [(2)2 + (-3b)2 + (-7c)2 – (2) (-3b) – (-3b) (-7c) – (-7c) (2)]
= (2 - 3b - 7c) (4 + 9b2 + 49c2 + 6b – 21bc + 14c)