Factorize:
(3a – 2b)3 + (2b – 5c)3 + (5c – 3a)3
We know that,
If, (x + y + z) = 0
Then (x3 + y3 + z3) = 3xyz
We have,
(3a – 2b) (2b – 5c) + (5c – 3a) = 0
So,
(3a – 2b)3 + (2b – 5c)3 + (5c – 3a)3 = 3 (3a – 2b) (2b – 5c) (5c – 3a)