Factorize:

(3a – 2b)3 + (2b – 5c)3 + (5c – 3a)3


We know that,


If, (x + y + z) = 0


Then (x3 + y3 + z3) = 3xyz


We have,


(3a – 2b) (2b – 5c) + (5c – 3a) = 0


So,


(3a – 2b)3 + (2b – 5c)3 + (5c – 3a)3 = 3 (3a – 2b) (2b – 5c) (5c – 3a)


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