Find the equivalent fraction of having:

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 9

(a)

3× 20 = 5× ….

3 × 2 × 2 × 5 = 5 × …

12 = …

Hence,

The required fraction is

(b)

3× … = 5× 9

5 × 3 × 3 = 3 × …

15 = …

Hence,

The required fraction is

(c)

3× 30 = 5× ….

3 × 2 × 3 × 5 = 5 × …

18 = …

Hence,

The required fraction is

(d)

3× … = 5× 27

5 × 3 × 3 × 3= 3 × …

45 = …

Hence,

The required fraction is