In a single throw of two coins, find the probability of getting (i) both tails, (ii) at least 1 tail,(iii) at the most 1 tail.


(i) A coin has two sides a head(H) and a tail(T), and there are two such coins.


There are Xm possible outcomes.


That is 22 = 4 and they are HH, HT, TH, TT


All possible outcomes are HH, HT, TH, TT.


Total number of outcomes = 4


Chances of getting 2 tails = 1, that is TT


Probability P() =


Probability of getting a tail P(both T) = =


(ii) A coin has two sides a head(H) and a tail(T), and there are two such coins.


There are Xm possible outcomes.


That is 22 = 4 and they are HH, HT, TH, TT


All possible outcomes are HH, HT, TH, TT.


Total number of outcomes = 4


Chances of getting atleast one tail = 3, that is HT, TH, TT.


Probability P() =


Probability of getting a tail P(atleast 1 T) = =


(iii) A coin has two sides a head(H) and a tail(T), and there are two such coins.


There are Xm possible outcomes.


That is 22 = 4 and they are HH, HT, TH, TT


All possible outcomes are HH, HT, TH, TT.


Total number of outcomes = 4


Chances of getting atmost 1 tail = 3, that is HT, TH, TT.


Probability P() =


Probability of getting a tail P(atmost 1 T) = =


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