It is known that a box of 100 electric bulbs contains 8 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective? (ii) non-defective?

(i) Total number of electric bulbs = 100

Number of defective bulbs = 8

Probability P() =

Probability of getting a defective bulbs P(d bulbs) = = =

(ii) Total number of electric bulbs = 100

Number of Non-defective bulbs = 100-8 = 92 (Number of electric bulbs – Number of defective bulbs)

Probability P() =

Probability of getting a Non- defective bulbs P(bulbs) = = =

7