A die is thrown at random. Find the probability of getting (i) 2 (ii) a number less than 3 (iii) a composite number (iv) a number not less than 4.

Question

Philoid · Accepted Answer

(i) Total number of outcomes = 6 (they are 1,2,3,4,5,6)

Chances of getting 2 on the die = 1

Probability P() =

Probability of getting 2 on die P(2) = =

(ii) Total number of outcomes = 6 (they are 1,2,3,4,5,6)

Chances of getting a number less than 3 on the die = 2 (They are 1,2)

Probability P() =

Probability of getting a number less than 3 on die P(less than 3)

= = =

(iii) Total number of outcomes = 6 (they are 1,2,3,4,5,6)

Composite number: A number which is not a prime number or a number which is divisible by numbers other than 1 and the number itself.

Chances of getting a composite number on the die = 2 (They are 4,6)

Probability P() =

Probability of getting a composite number on die the P(composite number)

= = =

(iv) Total number of outcomes = 6 (they are 1,2,3,4,5,6)

Chances of getting a number not less than 4 on the die = 4 (They are 4,5,6)

Probability P() =

Probability of getting a number not less than 4 on die P(not less than 4)

= = =