Here, we can observe that B × A = B

i.e. A = 1

Here,

First digit = B+1
Thus, 1 will be carried from 1+B² and becomes (B+1) (B² -9) B.
∴ C = B² -1
Now, all B, B+1 and B² -9 are one digit number.
This condition is satisfied for B=3 or B=4.
For B< 3, B² -9 will be negative.
For B>3, B² -9 will become a two digit number.
For B=3, C = 3² - 9 = 9-9 = 0
For B = 4, C = 4² -9 = 16-9 = 7

Hence, A=1, B=3, C = 0 or A=1, B=4, C = 7