Find the area of hexagon ABCDEF in which 
and 
such that 
cm, 
cm, 
cm, 
cm, 
cm, 
cm, 
cm, 
cm and 
cm.
Given: A Hexagon ABCDE
and 
cm
cm
cm
cm
cm
cm
cm
cm
cm
AL = AP + PL = 6 + 2 = 8 cm
PN = PL + LN = 2 + 8 = 10 cm
LM = LN + NM = 8 + 2 = 10 cm
ND = NM + MD =2 + 3 = 5 cm
Here,
Area (Hex. ABCDEF) = area (
APF) + area (
DEN) + area (
ABL) + area (
CMD)
+ area (Trap. PNEF) + area (Trap. LMCB)
Area of triangle = 
× (base) × (height).
Area of trapezium is 
× (sum of parallel sides) × height
Here,
Area (
APF) = 
× (AP) × (FP) = 
× (6) × (8) = 24 cm2.
Area (
DEN) = 
× (ND) × (EN) = 
× (5) × (12) = 30 cm2.
Area (
ABL) = 
× (AL) × (BL) = 
× (8) × (8) = 32 cm2.
Area (
CMD) = 
× (MD) × (CM) = 
× (3) × (6) = 9 cm2.
Area (Trap. PNEF) = 
× (FP + EN) × PN = 
× (8 + 12) × 10 = 100 cm2.
Area (Trap. LMCB) = 
× (BL + CM) × LM = 
× (8 + 6) × 10 = 70 cm2.
Area (Hex. ABCDEF) = area (
APF) + area (
DEN) + area (
ABL) + area (
CMD)
+ area (Trap. PNEF) + area (Trap. LMCB) = 24 + 30 + 32 + 9 + 100 + 70 = 265 cm2.
Area (Hex. ABCDEF) = 265 cm2