A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

Question

A silver ornament of mass &#x2018;m&#x2019; gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

Philoid · Accepted Answer

Mass of silver = ‘m’ g

Mass of gold = m/100 g

Number of atoms of silver(Ag) =

= {Atomic weight of Silver (Ag) = 108g/mole}

Number of atoms of gold(Au) =

=

Ratio of number of atoms of gold to silver = Au : Ag

= :

= 108 : 100 × 197

= 108 : 19700

= 1 : 182.41