Using second law of motion, derive the relation between force and acceleration. A bullet of 10 g strikes a sand-bag at a speed of 103 ms-1 and gets embedded after travelling 5 cm. Calculate:
(i) The resistive force exerted by the sand on the bullet
(ii) The time taken by the bullet to come to rest.
(i) Given,
m = 10g = kg
u = 103 m/s
v = 0, s = 5cm = m
v2 – u2 = 2as
0 – (103)2 = 2 × a ×
-(103) × (10)3 =
a = (-1000 × ) × 100
= -107 ms-2
F = ma
= 1/100x - 107
= -105 N
(ii) v = u +at
0 = (103) – 107 × t
t =
t = 10-4s