Multiply the following fractions:
(i)
(ii)
(iii) ![]()
(iv)
(v)
(vi) ![]()
(vii) ![]()
(i) We have,
× 5![]()
× ![]()
![]()
We have a improper fraction and now it can be written in terms of mixed fraction is as follows:
= 2![]()
(ii) We have,
6
× ![]()
× ![]()
![]()
We have an improper fraction and now it can be written in terms of mixed fraction is as follows:
= 4![]()
(iii)
× 5![]()
× ![]()
8
In this question, we have a whole number
(iv)
× 2![]()
× ![]()
![]()
We have an improper fraction and now it can be written in terms of mixed fraction is as follows:
= 2![]()
(v) 3
× ![]()
× ![]()
![]()
We have an improper fraction and now it can be written in terms of mixed fraction is as follows:
= 1![]()
(vi) 2
× 3
× 3
![]()
We have an improper fraction and now it can be written in terms of mixed fraction is as follows:
= 7![]()
(vii) 3
× ![]()
× ![]()
![]()
We have an improper fraction and now it can be written in terms of mixed fraction is as follows:
= 2![]()