Angles Q and R or a PQR are 25^o and 65^o. Write which of the following is true:

(i) PQ² + QR²= RP²

(ii) PQ² + RP²= QR²

(iii) RP² + QR²= PQ²

In the above question, it is given that:

In PQR, we have

∠Q = 25^o and ∠R = 65^o

We know that,

The sum of interior angles of a triangle = 180^o

∠PQR + ∠PRQ + ∠QPR = 180^o

25^o + 65^o + ∠QPR = 180^o

90^o + ∠QPR = 180^o

∠QPR = 180^o – 90^o

= 90^o

Hence, is right angled at point P

Thus,

By using Pythagoras theorem, we get:

(PR)² + (PQ)² = (QR)²

Hence,

Option (ii) is true