From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed (as shown in figure). Find the area of the remaining sheet.
It is given in the question that,
Radius of bigger circle = 14 cm
Area of the circle = πr2
∴ Area of bigger circle = 
× 14 × 14
= 22 × 2 × 14
= 44 × 14
= 616 cm2
Also, it is given that:
Radius of two small circles = 3.5 cm
Area of the circle = πr2
∴ Area of 2 small circles = 
= 44 × 0.5 × 3.5
= 22 × 3.5
= 77 cm2
Length of rectangle = 3 cm
Breadth of rectangle = 1 cm
Area of rectangle = Length × Breadth
∴ Area of rectangle = 3 × 1
= 3 cm2
Hence,
Remaining area of sheet = Area of bigger circle – Area of 2 small circles – Area of rectangle
= 616 – 77 – 3
= 616 – 80
= 536 cm2
10