Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m ∠EDF = 90^o.

Here,

According to the question,

We have to draw figure using following steps of construction:

Step 1: Draw a line segment DE of 5 cm

Step 2: Now, from point D draw a ray DX making an angle of 90° from DE and taking D as a center and radius 3 cm mark an arc intersecting DX at F.

Step 3: Join F to E.

Hence ΔDEF is the required triangle.