Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m ∠EDF = 90o.


Here,

According to the question,


We have to draw figure using following steps of construction:


Step 1: Draw a line segment DE of 5 cm



Step 2: Now, from point D draw a ray DX making an angle of 90° from DE and taking D as a center and radius 3 cm mark an arc intersecting DX at F.



Step 3: Join F to E.


Hence ΔDEF is the required triangle.



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