Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m ∠C= 60^o

Here,

According to the question,

We have to draw figure using following steps of construction:

Step 1: Draw a line segment BC of 7.5 cm

Step 2: Now, from point C draw a ray CX making an angle of 60° from BC.

Step 3: Now, taking C as a center and radius 5 cm mark an arc intersecting CX at A. Then, join A to B.

Hence ΔABC is the required triangle.