Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m ∠C= 60o


Here,

According to the question,


We have to draw figure using following steps of construction:


Step 1: Draw a line segment BC of 7.5 cm



Step 2: Now, from point C draw a ray CX making an angle of 60° from BC.



Step 3: Now, taking C as a center and radius 5 cm mark an arc intersecting CX at A. Then, join A to B.


Hence ΔABC is the required triangle.



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