Construct the right-angled ΔPQR, where m ∠Q =90o, QR =8cm and PR = 10cm.
Here,
According to the question,
We have to draw figure using following steps of construction:
Step 1: Draw a line segment QR of 8 cm
Step 2: Now, From Q construct a ray QX making an angle of 90° with QR.
Step 3: Take R as a center and radius of 10cm draw an arc intersecting QX at P
Step 4: Now, join RP
Hence, ΔPQR is the required triangle.