The zeroes of the polynomial p (x) = x2 – 3x are
We have,
p (x) = x2 – 3x
∴ Zeros of p (x) are:
p (x) = 0
x2 – 3x = 0
x (x – 3) = 0
So, x = 0
And, x – 3 = 0
x = 3
Thus, zeros of the given polynomial are 0 and 3
Hence, option B is correct