In the given figure, BE ⊥ CA and CF ⊥ BA such that BE=CF. Then, which of the following is true?
From the given figure, we have
BE is perpendicular to CA
Also, CF is perpendicular to BA
And, BE = CF
Now, in ∆ABE and ∆ACF we have:
BE = CF (Given)
∠BEA = ∠CFA = 90o
∠A = ∠A (Common)
∴ By AAS congruence criterion
∆ABE ≅ ∆ACF
Hence, option (A) is correct