When ethanoic acid reacts with sodium hydrogencarbonate, a salt X is formed and a gas Y is evolved.

(a) Identify X and Y. Write chemical equation of reaction involved.

(b) Describe an activity and draw the diagram of the apparatus to prove that the evolved gas is the one which you have named.

OR

Look at Figure and answer the following questions.

(a) What change would you observe in tube B containing calcium hydroxide solution

(b) Write the reaction involved in test tubes A and B respectively

(c) If ethanol is given instead of acetic acid, would you expect the same change?

(d) How can a solution of lime water be prepared in the laboratory?

(a) X is Sodium ethanoate and Y is CO₂. The reaction is as follows:

CH₃COOH + NaHCO₃ → CH₃COONa + CO₂ +H₂O

(b) Take NaHCO₃ in a test tube and add 2ml of ethanoic acid. CO₂ is evolved with brisk effervescence. Pass the gas through freshly prepared lime water. The lime water turns milky. The apparatus is as follows:

OR

(a) It will turn milky due to the formation of CaCO₃ in reaction with CO₂.

(b) The reaction involved in test tube A is as follows:

2CH₃COOH + Na₂CO₃ → 2CH₃COONa + CO₂ + H₂O

The reaction involved in test tube B is as follows:

CO₂ + Ca(OH)₂ → CaCO₃ + H₂O

(c) No reaction will take place since ethanol is weakly acidic and cannot react with Na₂CO₃ to give CO₂ gas.

(d) Lime water is prepared by the reaction of calcium oxide (Quick lime) with water followed by the decantation or filtering of supernatant liquid.

CaO + H₂O → Ca(OH)₂