2s² - (1 + 22)s + 2.

By splitting the middle term

2s² - (1 + 2√2) s + √2 = 0

2s² - s - 2√2s + √2 = 0

s (2s - 1) - √2(2s - 1) = 0

(2s - 1)(s - √2) = 0

⇒ s = 1/2, √2

Verification:

Sum of the zeroes = - (coefficient of x) ÷ coefficient of x²

α + β = - b/a

(1/2) + (√2) = - {(1 + 2√2)}/2

= - (1 + 2√2)/2 = - (1 + 2√2)/2

Product of the zeroes = constant term ÷ coefficient of x²

α β = c/a

(1/2)(√2) = √2/2

1/√2 = 1/√2